Gravitational Potential Energy (Eₚ = mgh)

✏️ Paper first! Work out every question on paper before you tap Show solution. Write down every step – the equation, the numbers with units, the rearranging and the answer with its unit. In the exam, if your final answer is wrong you can still get marks for correct working, but only if the examiner can see it.

Course: Combined Science + Separate Physics  |  Tier: Foundation + Higher  |  Equation sheet: given in the exam

The equation

gravitational potential energy = mass × gravitational field strength × height    Eₚ = m g h

QuantitySymbolUnit
gravitational potential energyEₚjoules (J)
massmkilograms (kg)
gravitational field strengthgnewtons per kilogram (N/kg)
heighthmetres (m)

Rearranged: h = Eₚ ÷ (m g)  |  m = Eₚ ÷ (g h)  |  g = Eₚ ÷ (m h)  |  On Earth, g = 9.8 N/kg

Use FIFA for every answer

  • F – Formula: write the equation as it appears on the sheet.
  • I – Insert: put in the numbers (convert to standard units first).
  • F – Fix: rearrange to make the unknown the subject.
  • A – Answer: calculate and always give the unit.

Foundation: aim for Q1–8.   Higher: aim for Q4–10. Most questions need rearranging.


Questions

Q1 (F) A 2.0 kg school bag is lifted 1.5 m onto a table. Calculate the gain in gravitational potential energy. (g = 9.8 N/kg)

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F: Eₚ = m g h
I: Eₚ = 2.0 × 9.8 × 1.5
F: Eₚ is already the subject
A: 29.4 J

Q2 (F) A 50 kg climber gains 9800 J of gravitational potential energy on a climbing wall. How high does she climb? (g = 9.8 N/kg)

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F: Eₚ = m g h
I: 9800 = 50 × 9.8 × h, so 9800 = 490 × h
F: h = 9800 ÷ 490
A: 20 m

Q3 (F) A forklift lifts a crate 4.0 m, giving it 1960 J of gravitational potential energy. Calculate the mass of the crate. (g = 9.8 N/kg)

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F: Eₚ = m g h
I: 1960 = m × 9.8 × 4.0, so 1960 = 39.2 × m
F: m = 1960 ÷ 39.2
A: 50 kg

Q4 (F) A 250 g apple falls from a tree and loses 4.9 J of gravitational potential energy. How far does it fall? (g = 9.8 N/kg)

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Convert first: 250 g = 0.25 kg
F: Eₚ = m g h
I: 4.9 = 0.25 × 9.8 × h, so 4.9 = 2.45 × h
F: h = 4.9 ÷ 2.45
A: 2 m

Q5 (F) A 60 kg hiker gains 294 kJ of gravitational potential energy climbing a hill. How high is the hill? (g = 9.8 N/kg)

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Convert first: 294 kJ = 294 000 J
F: Eₚ = m g h
I: 294 000 = 60 × 9.8 × h, so 294 000 = 588 × h
F: h = 294 000 ÷ 588
A: 500 m

Q6 (F/H) On the Moon, an astronaut lifts a 20 kg rock 1.5 m. It gains 48 J of gravitational potential energy. Calculate g on the Moon.

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F: Eₚ = m g h
I: 48 = 20 × g × 1.5, so 48 = 30 × g
F: g = 48 ÷ 30
A: 1.6 N/kg

Q7 (F/H) A lift and its passengers have a total mass of 1200 kg. The lift gains 352.8 kJ of gravitational potential energy. How high does it rise? (g = 9.8 N/kg)

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Convert first: 352.8 kJ = 352 800 J
F: Eₚ = m g h
I: 352 800 = 1200 × 9.8 × h, so 352 800 = 11 760 × h
F: h = 352 800 ÷ 11 760
A: 30 m

Q8 (F/H) The water in a hydroelectric reservoir stores 2.94 × 1012 J of gravitational potential energy, 150 m above the turbines. Calculate the mass of water. (g = 9.8 N/kg)

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F: Eₚ = m g h
I: 2.94 × 1012 = m × 9.8 × 150, so 2.94 × 1012 = 1470 × m
F: m = 2.94 × 1012 ÷ 1470
A: 2.0 × 109 kg

Q9 (H) A 60 kg diver steps off a 10 m diving board. Calculate her speed as she enters the water. (g = 9.8 N/kg; ignore air resistance)

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Step 1 – GPE lost: Eₚ = m g h = 60 × 9.8 × 10 = 5880 J = Eₖ gained
Step 2 – speed
F: Eₖ = ½ m v²
I: 5880 = 0.5 × 60 × v², so 5880 = 30 × v²
F: v² = 196, so v = √196
A: 14 m/s

Q10 (H) A pumped-storage power station transfers 1.8 × 108 J to lift water 320 m uphill. Calculate the mass of water lifted, in standard form to 2 significant figures. (g = 9.8 N/kg)

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F: Eₚ = m g h
I: 1.8 × 108 = m × 9.8 × 320, so 1.8 × 108 = 3136 × m
F: m = 1.8 × 108 ÷ 3136 = 57 397… kg
A: 5.7 × 104 kg (2 s.f.)