Density = Mass ÷ Volume (ρ = m/V)

✏️ Paper first! Work out every question on paper before you tap Show solution. Write down every step – the equation, the numbers with units, the rearranging and the answer with its unit. In the exam, if your final answer is wrong you can still get marks for correct working, but only if the examiner can see it.

Course: Combined Science + Separate Physics  |  Tier: Foundation + Higher  |  Equation sheet: given in the exam

The equation

density = mass ÷ volume    ρ = m / V

QuantitySymbolUnit
densityρkilograms per cubic metre (kg/m³)
massmkilograms (kg)
volumeVcubic metres (m³)

Rearranged: m = ρ × V  |  V = m ÷ ρ  |  1 cm³ = 1 × 10−6 m³; 1 litre = 0.001 m³; 1 g/cm³ = 1000 kg/m³

Use FIFA for every answer

  • F – Formula: write the equation as it appears on the sheet.
  • I – Insert: put in the numbers (convert to standard units first).
  • F – Fix: rearrange to make the unknown the subject.
  • A – Answer: calculate and always give the unit.

Foundation: aim for Q1–8.   Higher: aim for Q4–10. Most questions need rearranging.


Questions

Q1 (F) A block of plastic has a mass of 2 kg and a volume of 0.001 m³. Calculate its density.

Show solution

F: ρ = m / V
I: ρ = 2 ÷ 0.001
F: ρ is already the subject
A: 2000 kg/m³

Q2 (F) A bath holds 0.2 m³ of water (ρ = 1000 kg/m³). Calculate the mass of the water.

Show solution

F: ρ = m / V
I: 1000 = m ÷ 0.2
F: m = 1000 × 0.2
A: 200 kg

Q3 (F) A 540 kg batch of aluminium (ρ = 2700 kg/m³) arrives at a factory. Calculate its volume.

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F: ρ = m / V
I: 2700 = 540 ÷ V
F: V = 540 ÷ 2700
A: 0.2 m³

Q4 (F) A gold ring has a mass of 19.3 g and a volume of 1.0 cm³. Calculate its density in kg/m³.

Show solution

Convert first: 19.3 g = 0.0193 kg; 1.0 cm³ = 1.0 × 10−6 m³
F: ρ = m / V
I: ρ = 0.0193 ÷ 1.0 × 10−6
F: ρ is already the subject
A: 19 300 kg/m³

Q5 (F) Olive oil has a density of 920 kg/m³. Calculate the mass of a 1.5 litre bottle of oil.

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Convert first: 1.5 litres = 0.0015 m³
F: ρ = m / V
I: 920 = m ÷ 0.0015
F: m = 920 × 0.0015
A: 1.38 kg

Q6 (F/H) A 260 g stone is lowered into a measuring cylinder. The water level rises from 50 cm³ to 150 cm³. Calculate the density of the stone in kg/m³.

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Volume of stone: 150 − 50 = 100 cm³ = 1.0 × 10−4 m³; mass = 0.26 kg
F: ρ = m / V
I: ρ = 0.26 ÷ 1.0 × 10−4
F: ρ is already the subject
A: 2600 kg/m³

Q7 (F/H) A bedroom is 5 m long, 4 m wide and 2.5 m high. Air has a density of 1.2 kg/m³. Calculate the mass of air in the room.

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Volume: 5 × 4 × 2.5 = 50 m³
F: ρ = m / V
I: 1.2 = m ÷ 50
F: m = 1.2 × 50
A: 60 kg

Q8 (F/H) The Earth has an average density of 5.5 × 103 kg/m³ and a volume of 1.1 × 1021 m³. Calculate its mass, to 2 significant figures.

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F: ρ = m / V
I: 5.5 × 103 = m ÷ 1.1 × 1021
F: m = 5.5 × 103 × 1.1 × 1021 = 6.05 × 1024 kg
A: 6.1 × 1024 kg (2 s.f.)

Q9 (H) A block of ice has a volume of 0.50 m³. Ice has a density of 920 kg/m³. Calculate the weight of the block. (g = 9.8 N/kg)

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Step 1 – mass
F: ρ = m / V
I: 920 = m ÷ 0.50
F: m = 920 × 0.50 = 460 kg
Step 2 – weight
W = m g = 460 × 9.8
A: 4508 N

Q10 (H) A metal cube has sides of 4.0 cm and a mass of 170 g. Calculate its density in kg/m³, to 2 significant figures.

Show solution

Volume: 4.0 × 4.0 × 4.0 = 64 cm³ = 6.4 × 10−5 m³; mass = 0.170 kg
F: ρ = m / V
I: ρ = 0.170 ÷ 6.4 × 10−5
F: ρ = 2656 kg/m³
A: 2700 kg/m³ (2 s.f.)