Maths Skills for Physics

✏️ Paper first! Work out every question on paper before you tap Show solution. Write down every step – the equation, the numbers with units, the rearranging and the answer with its unit. In the exam, if your final answer is wrong you can still get marks for correct working, but only if the examiner can see it.

Most lost marks in calculation questions come from the maths, not the physics. Learn these, then try the 12 practice questions at the bottom.

1. Rearranging equations

  • Golden rule: whatever you do to one side, do to the other.
  • Undo in reverse order: to get v on its own in Eₖ = ½mv², first multiply by 2, then divide by m, then square root: v = √(2Eₖ ÷ m).
  • Tip: it’s often easier to put the numbers in first, then rearrange. You get a mark for the correct substitution either way.
  • Squared or square-rooted? If the unknown is squared (v², e², I²), square-root at the very end. Forgetting this is one of the most common errors.

2. Unit conversions

Always convert to standard units before you substitute.

QuantityConvertHow
Timeminutes → s; hours → s× 60; × 3600
Lengthmm → m; cm → m; km → m÷ 1000; ÷ 100; × 1000
Massg → kg; tonnes → kg÷ 1000; × 1000
Areacm² → m²÷ 10 000
Volumecm³ → m³; litres → m³÷ 1 000 000; ÷ 1000
EnergykJ → J; MJ → J× 1000; × 106
PowerkW → W; MW → W× 1000; × 106
CurrentmA → A÷ 1000
Speedkm/h → m/s÷ 3.6

3. Standard form

  • A number between 1 and 10, multiplied by a power of 10: 6 200 000 = 6.2 × 106; 0.00045 = 4.5 × 10−4.
  • On a calculator use the ×10x (or EXP) key: type 3.0 ×10x 8 for 3.0 × 108. Don’t type “× 10” as well.
  • Use brackets when dividing by a number in standard form.

4. Significant figures

  • Give your answer to the same number of significant figures as the least precise data in the question (usually 2 or 3).
  • Count from the first non-zero digit: 0.04672 to 2 s.f. is 0.047.
  • Don’t round in the middle of a multi-step calculation – keep the full calculator value until the end.

5. Graphs

  • Gradient = change in y ÷ change in x. Use a large triangle for accuracy.
  • Curved line: draw a tangent (a straight line just touching the curve) and find its gradient.
  • Area under a velocity–time graph = distance travelled (HT). Split into rectangles and triangles.
  • Directly proportional: a straight line through the origin. Inversely proportional: doubling one quantity halves the other.

6. Percentages and efficiency

  • Efficiency = useful ÷ total. Multiply by 100 for a percentage. It can never be more than 1 (100%).
  • Percentage difference = (difference ÷ true value) × 100.

Practice questions

Q1 Rearrange V = IR to make I the subject.

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Divide both sides by R: I = V ÷ R

Q2 Rearrange Eₖ = ½mv² to make v the subject.

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× 2: 2Eₖ = mv²
÷ m: v² = 2Eₖ ÷ m
√: v = √(2Eₖ ÷ m)

Q3 Convert 2.5 km to metres and 45 minutes to seconds.

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2.5 × 1000 = 2500 m; 45 × 60 = 2700 s

Q4 Convert 350 g to kg and 25 cm to m.

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350 ÷ 1000 = 0.35 kg; 25 ÷ 100 = 0.25 m

Q5 Convert 1.2 kW to W and 3.5 MJ to J (in standard form).

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1.2 × 1000 = 1200 W; 3.5 × 106 J

Q6 A block’s base is 500 cm². What is this in m²?

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1 m² = 10 000 cm², so 500 ÷ 10 000 = 0.05 m². (Not ÷ 100 – that’s a common mistake.)

Q7 Write 0.00045 and 6 200 000 in standard form.

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4.5 × 10−4 and 6.2 × 106

Q8 Calculate (3.0 × 108) × (2.0 × 10−3).

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3.0 × 2.0 = 6.0; 108 × 10−3 = 105, so 6.0 × 105

Q9 Round 0.04672 to 2 s.f. and 23 856 to 3 s.f.

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0.047 and 23 900

Q10 A velocity–time graph is a straight line from (0 s, 0 m/s) to (8.0 s, 24 m/s). Find the acceleration.

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Gradient = 24 ÷ 8.0 = 3.0 m/s²

Q11 A motor gives 450 J of useful energy from 600 J supplied. Calculate its efficiency as a percentage.

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450 ÷ 600 = 0.75 → 75%

Q12 A student measures the specific heat capacity of water as 4410 J/kg °C. The true value is 4200 J/kg °C. Calculate the percentage difference.

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Difference = 4410 − 4200 = 210
(210 ÷ 4200) × 100 = 5%