The Physics Question Bank

Ramped Questions for GCSE Physics

GCSE Energy

Kinetic Energy Calculations

10 Kinetic Energy Equation QuestionsDownload

Answers

  1. KE = ½ × 0.16 × 25² = 50 J
  2. KE = ½ × 12 × 2.5² = 37.5 J
  3. KE = ½ × 70 × 4² = 560 J
  4. KE = ½ × 1300 × 13.4² = 116 714 J
  5. v = √(2 × 39 600 ÷ 220) = 18.97 m/s
  6. v = √(2 × 86 ÷ 0.43) = 20 m/s
  7. v = √(2 × 3600 ÷ 80) = 9.49 m/s
  8. KE = ½ × 38 000 × 20² = 7.6 × 10⁶ J
  9. v = √(2 × 1 440 000 ÷ 4500) = 25.3 m/s

10a. KE = ½ × 1800 × 10² = 90 000 J

10b. KE = ½ × 1800 × 25² = 562 500 J

10c. Increase in KE = 562 500 − 90 000 = 472 500 J

Gravitational Potential Energy Calculations

10 Ramped Gravitational Potential Energy EquationDownload

Answers

  1. GPE = 1.5 × 10 × 0.8 = 12 J
  2. GPE = 4 × 10 × 3 = 120 J
  3. GPE = 12 × 10 × 2.2 = 264 J
  4. GPE = 60 × 10 × 5 = 3000 J
  5. h = 1000 ÷ (25 × 10) = 4 m
  6. m = 9000 ÷ (10 × 15) = 60 kg
  7. h = 28000 ÷ (350 × 10) = 8 m
  8. h = 16000 ÷ (80 × 10) = 20 m
  9. h = 125000 ÷ (500 × 10) = 25 m
  10. h = 54000 ÷ (90 × 10) = 60 m

Elastic Potential Energy Calculations

Elastic Potential Energy – 10 Ramped GCSE Physics Calculation QuestionsDownload

Answers

  1. EPE = ½ × 120 × 0.15² = 1.35 J
  2. EPE = ½ × 350 × 0.25² = 10.94 J
  3. EPE = ½ × 500 × 0.20² = 10 J
  4. EPE = ½ × 800 × 0.18² = 12.96 J
  5. k = (2 × 180) ÷ 0.60² = 1000 N/m
  6. k = (2 × 2500) ÷ 0.50² = 20 000 N/m
  7. e = √(2 × 4500 ÷ 25000) = 0.60 m
  8. e = √(2 × 1080 ÷ 1500) = 1.20 m

9a. EPE = ½ × 40 000 × 0.35² = 2450 J

9b. EPE = 2450 ÷ 1000 = 2.45 kJ

10a. EPE = ½ × 60 000 × 0.40² = 4800 J

10b. EPE = ½ × 60 000 × 0.80² = 19 200 J

10c. Increase in EPE = 19 200 − 4800 = 14 400 J

10d. Doubling the compression from 0.40 m to 0.80 m increases the energy from 4800 J to 19 200 J (4× larger) because elastic potential energy is proportional to extension².

Specific Heat Capacity Calculations

Specific Heat Capacity Calculation QuestionsDownload

Answers

  1. c = 168000 ÷ (2.0 × 20) = 4200 J/kg°C
  2. E = 0.25 × 4200 × 20 = 21000 J
  3. E = 1.5 × 4200 × 30 = 189000 J
  4. ΔT = 6720000 ÷ (80 × 4200) = 20°C
  5. E = 2.0 × 900 × 100 = 180000 J
  6. E = 150 × 800 × 120 = 14400000 J
  7. E = 450 × 950 × 8 = 3420000 J
  8. c = 180000 ÷ (4.0 × 50) = 900 J/kg°C
  9. E = 120000 × 4200 × 5 = 2.52 × 10⁹ J

10a. ΔT = 75 − 18 = 57°C

10b. E = 500 × 1200 × 57 = 34200000 J

10c. Energy = 34200000 ÷ 3600000 = 9.5 kWh

Efficiency Calculation involving Energy and Power

Efficiency Calculations – GCSE Physics (1)Download

Answers

  1. Efficiency = 18 ÷ 120 = 0.15 = 15%
  2. Efficiency = 400 ÷ 500 = 0.80 = 80%
  3. Efficiency = 8100 ÷ 9000 = 0.90 = 90%
  4. Efficiency = 5000 ÷ 25000 = 0.20 = 20%
  5. Efficiency = 16000 ÷ 80000 = 0.20 = 20%
  6. Useful energy = 0.80 × 2000 = 1600 J
  7. Useful energy = 0.35 × 80000 = 28000 J
  8. Total input energy = 1200 ÷ 0.15 = 8000 J
  9. Useful energy = 0.90 × 250000 = 225000 J
  10. a) Efficiency = 320000 ÷ 400000 = 0.80 = 80%, b) wasted energy = 400000 − 320000 = 80000 J
  11. Efficiency = 1750 ÷ 2500 = 0.70 = 70%
  12. Useful power = 0.65 × 1200 = 780 W
  13. Input power = 420 ÷ 0.70 = 600 W
  14. Useful power = 600 − 150 = 450 W, efficiency = 450 ÷ 600 = 0.75 = 75%
  15. Efficiency = 4.5 ÷ 6.0 = 0.75 = 75%
  16. a) Useful power = 0.85 × 12000 = 10200 W, b) wasted power = 12000 − 10200 = 1800 W
  17. Efficiency = 18 ÷ 25 = 0.72 = 72%
  18. Input power = 2.4 ÷ 0.80 = 3.0 MW
  19. a) Useful power = 0.40 × 5.0 = 2.0 MW, b) wasted power = 5.0 − 2.0 = 3.0 MW
  20. a) Efficiency = 120 ÷ 150 = 0.80 = 80%, b) wasted power = 150 − 120 = 30 kW, c) wasted percentage = 20%