GCSE Particle Model of Matter

Density calculations using m/V

Answers to Density Questions

  1. Density = 19.3 ÷ 1.0 = 19.3 g/cm³
  2. Density = 240 ÷ 600 = 0.40 g/cm³
  3. Density = 1380 ÷ 1500 = 0.92 g/cm³
  4. Mass = 7.8 × 5 = 39 g
  5. Mass = 2.7 × 40 = 108 g
  6. Mass = 50000 g = 50 kg
  7. Volume = 105 ÷ 10.5 = 10 cm³
  8. Volume = 60 ÷ 1.2 = 50 cm³
  9. Mass = 1030 × 25 = 25750 kg
  10. Volume = 18 ÷ 2400 = 0.0075 m³
  11. Mass = 1000 × 0.120 = 120 kg
  12. Mass = 2700 × 0.08 = 216 kg
  13. Mass = 750 × 0.060 = 45 kg
  14. Density = 480 ÷ 0.60 = 800 kg/m³
  15. Volume = 3.6 ÷ 7200 = 0.0005 m³
  16. Mass = 1000 × 0.250 = 250 kg; weight = 250 × 10 = 2500 N
  17. Mass = 8900 × 0.500 = 4450 kg, so it exceeds the 4000 kg van limit.

Latent Heat Calculation Questions

Answers to Latent Heat Calculations

  1. Mass = 167000 ÷ 334000 = 0.50 kg
  2. Mass = 668000 ÷ 334000 = 2.0 kg
  3. Mass = 452000 ÷ 2260000 = 0.20 kg
  4. Energy = 0.80 × 2260000 = 1808000 J
  5. Energy = 2.5 × 334000 = 835000 J
  6. Mass = 6780000 ÷ 2260000 = 3.0 kg
  7. Mass = 1002000 ÷ 334000 = 3.0 kg
  8. Energy = 5.0 × 2260000 = 11300000 J = 1.13 × 10⁷ J
  9. Mass = (1.67 × 10⁷) ÷ 334000 = 50 kg
  10. Mass = (1.695 × 10⁷) ÷ 2260000 = 7.5 kg

Calculation Questions Using p₁V₁ = p₂V₂

Answers to p₁V₁ = p₂V₂ Questions

  1. p₂ = (100 × 60) ÷ 30 = 200 kPa
  2. V₂ = (200 × 120) ÷ 100 = 240 cm³
  3. p₂ = (100 × 50) ÷ 80 = 62.5 kPa
  4. V₂ = (120 × 2.0) ÷ 80 = 3.0 m³
  5. V₂ = (500 × 40) ÷ 250 = 80 cm³
  6. p₂ = (100 × 300) ÷ 100 = 300 kPa
  7. V₂ = (100 × 5.0) ÷ 25 = 20.0 m³
  8. V₂ = (100 × 250) ÷ 250 = 100 cm³
  9. V₂ = (400 × 10) ÷ 100 = 40 cm³
  10. p₂ = (180 × 0.50) ÷ 0.90 = 100 kPa
  11. V₂ = (100 × 3.0) ÷ 50 = 6.0 m³
  12. V₂ = (160 × 250) ÷ 400 = 100 cm³
  13. V₂ = (300 × 0.75) ÷ 120 = 1.875 m³
  14. p₂ = (2.4 × 10⁵ × 0.20) ÷ 0.12 = 4.0 × 10⁵ Pa
  15. V₂ = (3.0 × 10⁵ × 8.0 × 10⁻³) ÷ (4.8 × 10⁵) = 5.0 × 10⁻³ m³
  16. V₂ = (5.0 × 10⁵ × 2.5 × 10⁻⁴) ÷ (1.0 × 10⁵) = 1.25 × 10⁻³ m³
  17. V₂ = (1.2 × 10⁶ × 0.015) ÷ (3.0 × 10⁵) = 0.060 m³