Potential Difference = Current × Resistance (V = IR)

✏️ Paper first! Work out every question on paper before you tap Show solution. Write down every step – the equation, the numbers with units, the rearranging and the answer with its unit. In the exam, if your final answer is wrong you can still get marks for correct working, but only if the examiner can see it.

Course: Combined Science + Separate Physics  |  Tier: Foundation + Higher  |  Equation sheet: given in the exam

The equation

potential difference = current × resistance    V = I R

QuantitySymbolUnit
potential differenceVvolts (V)
currentIamperes (A)
resistanceRohms (Ω)

Rearranged: I = V ÷ R  |  R = V ÷ I  |  1 kΩ = 1000 Ω; 1 mA = 0.001 A

Use FIFA for every answer

  • F – Formula: write the equation as it appears on the sheet.
  • I – Insert: put in the numbers (convert to standard units first).
  • F – Fix: rearrange to make the unknown the subject.
  • A – Answer: calculate and always give the unit.

Foundation: aim for Q1–8.   Higher: aim for Q4–10. Most questions need rearranging.


Questions

Q1 (F) A current of 2 A flows through a 6 Ω resistor in a toy car. Calculate the potential difference across it.

Show solution

F: V = I R
I: V = 2 × 6
F: V is already the subject
A: 12 V

Q2 (F) A heater with a resistance of 46 Ω is connected to the 230 V mains. Calculate the current.

Show solution

F: V = I R
I: 230 = I × 46
F: I = 230 ÷ 46
A: 5 A

Q3 (F) A 9 V battery makes a current of 0.3 A flow through a lamp. Calculate the resistance of the lamp.

Show solution

F: V = I R
I: 9 = 0.3 × R
F: R = 9 ÷ 0.3
A: 30 Ω

Q4 (F) An LED needs a p.d. of 3.0 V and a current of 20 mA. Calculate its resistance.

Show solution

Convert first: 20 mA = 0.020 A
F: V = I R
I: 3.0 = 0.020 × R
F: R = 3.0 ÷ 0.020
A: 150 Ω

Q5 (F) A 2.0 kΩ resistor in a phone circuit has 12 V across it. Calculate the current in mA.

Show solution

Convert first: 2.0 kΩ = 2000 Ω
F: V = I R
I: 12 = I × 2000
F: I = 12 ÷ 2000 = 0.006 A
A: 6 mA

Q6 (F/H) A 6 Ω and a 4 Ω resistor are connected in series to a 5 V battery. Calculate the current.

Show solution

Total resistance in series: 6 + 4 = 10 Ω
F: V = I R
I: 5 = I × 10
F: I = 5 ÷ 10
A: 0.5 A

Q7 (F/H) A thermistor in a fridge sensor has a resistance of 1.5 kΩ. A current of 4 mA flows through it. Calculate the p.d. across it.

Show solution

Convert first: 1.5 kΩ = 1500 Ω; 4 mA = 0.004 A
F: V = I R
I: V = 0.004 × 1500
F: V is already the subject
A: 6 V

Q8 (F/H) Dry human skin can have a resistance of 1.0 × 105 Ω. Calculate the current if someone touches a 230 V wire. Give your answer in standard form.

Show solution

F: V = I R
I: 230 = I × 1.0 × 105
F: I = 230 ÷ 1.0 × 105
A: 2.3 × 10−3 A

Q9 (H) 90 C of charge flows through a 20 Ω resistor in 30 s. Calculate the p.d. across the resistor.

Show solution

Step 1 – current
F: Q = I t
I: 90 = I × 30
F: I = 90 ÷ 30 = 3 A
Step 2 – p.d.
F: V = I R
I: V = 3 × 20
A: 60 V

Q10 (H) A 1.5 V AA cell makes a current of 0.28 A flow through a bulb. Calculate the bulb’s resistance, to 2 significant figures.

Show solution

F: V = I R
I: 1.5 = 0.28 × R
F: R = 1.5 ÷ 0.28
A: 5.357… = 5.4 Ω (2 s.f.)